q 1 ( t = 0 ) = 1 q 2 ( t = 0 ) = 0 q 3 ( t = 0 ) = 0 {\displaystyle {\begin{array}{ccc}q_{1}(t=0)&=&1\\q_{2}(t=0)&=&0\\q_{3}(t=0)&=&0\end{array}}}
d q 1 d t = − ( k 13 + k 12 ) ⋅ q 1 + k 31 q 3 d q 2 d t = k 12 ⋅ q 1 d q 3 d t = k 13 ⋅ q 1 − k 31 q 3 {\displaystyle {\begin{array}{ccc}{\overset {\text{ }}{\frac {\mathrm {d} q_{1}}{\mathrm {d} t}}}&=&-\left(k_{13}+k_{12}\right)\cdot q_{1}+k_{31}q_{3}\\{\overset {\text{ }}{\frac {\mathrm {d} q_{2}}{\mathrm {d} t}}}&=&k_{12}\cdot q_{1}\\{\overset {\text{ }}{\frac {\mathrm {d} q_{3}}{\mathrm {d} t}}}&=&k_{13}\cdot q_{1}-k_{31}q_{3}\end{array}}}
q 1 = A 1 e l 1 t + A 2 e l 2 t q 2 = 1 − A 3 e l 1 t − A 4 e l 2 t q 3 = − A 5 e l 1 t + A 5 e l 2 t {\displaystyle {\begin{array}{ccc}q_{1}&=&A_{1}e^{l_{1}t}+A_{2}e^{l_{2}t}\\q_{2}&=&1-A_{3}e^{l_{1}t}-A_{4}e^{l_{2}t}\\q_{3}&=&-A_{5}e^{l_{1}t}+A_{5}e^{l_{2}t}\end{array}}}
d q 1 d t = l 1 A 1 e l 1 t + l 2 A 2 e l 2 t d q 2 d t = − l 1 A 3 e l 1 t − l 2 A 4 e l 2 t d q 3 d t = − l 1 A 5 e l 1 t + l 2 A 5 e l 2 t {\displaystyle {\begin{array}{ccc}{\overset {\text{ }}{\frac {\mathrm {d} q_{1}}{\mathrm {d} t}}}&=&l_{1}A_{1}e^{l_{1}t}+l_{2}A_{2}e^{l_{2}t}\\{\overset {\text{ }}{\frac {\mathrm {d} q_{2}}{\mathrm {d} t}}}&=&-l_{1}A_{3}e^{l_{1}t}-l_{2}A_{4}e^{l_{2}t}\\{\overset {\text{ }}{\frac {\mathrm {d} q_{3}}{\mathrm {d} t}}}&=&-l_{1}A_{5}e^{l_{1}t}+l_{2}A_{5}e^{l_{2}t}\end{array}}}
− ( k 13 + k 12 ) ⋅ q 1 + k 31 q 3 = − ( k 13 + k 12 ) ( A 1 e l 1 t + A 2 e l 2 t ) + k 31 ( − A 5 e l 1 t + A 2 e l 2 t ) k 12 ⋅ q 1 = k 12 ( A 1 e l 1 t + A 2 e l 2 t ) k 13 ⋅ q 1 − k 31 q 3 = k 13 ⋅ ( A 1 e l 1 t + A 2 e l 2 t ) − k 31 ( − A 5 e l 1 t + A 5 e l 2 t ) {\displaystyle {\begin{array}{ccc}-\left(k_{13}+k_{12}\right)\cdot q_{1}+k_{31}q_{3}&=&-\left(k_{13}+k_{12}\right)\left(A_{1}e^{l_{1}t}+A_{2}e^{l_{2}t}\right)+k_{31}\left(-A_{5}e^{l_{1}t}+A_{2}e^{l_{2}t}\right)\\k_{12}\cdot q_{1}&=&k_{12}\left(A_{1}e^{l_{1}t}+A_{2}e^{l_{2}t}\right)\\k_{13}\cdot q_{1}-k_{31}q_{3}&=&k_{13}\cdot \left(A_{1}e^{l_{1}t}+A_{2}e^{l_{2}t}\right)-k_{31}\left(-A_{5}e^{l_{1}t}+A_{5}e^{l_{2}t}\right)\end{array}}}
l 1 A 1 = − ( k 13 + k 12 ) A 1 − k 31 A 5 l 2 A 2 = − ( k 13 + k 12 ) A 2 + k 31 A 5 − l 1 A 3 = k 12 A 1 − l 2 A 4 = k 12 A 2 − l 1 A 5 = k 13 A 1 + k 31 A 5 − l 2 A 5 = k 13 A 2 − k 31 A 5 1 = A 1 + A 2 0 = 1 − A 3 − A 4 0 = − A 5 + A 5 {\displaystyle {\begin{array}{ccc}l_{1}A_{1}&=&-\left(k_{13}+k_{12}\right)A_{1}-k_{31}A_{5}\\l_{2}A_{2}&=&-\left(k_{13}+k_{12}\right)A_{2}+k_{31}A_{5}\\-l_{1}A_{3}&=&k_{12}A_{1}\\-l_{2}A_{4}&=&k_{12}A_{2}\\-l_{1}A_{5}&=&k_{13}A_{1}+k_{31}A_{5}\\-l_{2}A_{5}&=&k_{13}A_{2}-k_{31}A_{5}\\1&=&A_{1}+A_{2}\\0&=&1-A_{3}-A_{4}\\0&=&-A_{5}+A_{5}\end{array}}}
l 1 = − k 12 A 1 A 3 l 2 = − k 12 A 2 A 4 1 = A 1 + A 2 1 = A 3 + A 4 {\displaystyle {\begin{array}{ccc}l_{1}&=&-{\frac {k_{12}A_{1}}{A_{3}}}\\l_{2}&=&-{\frac {k_{12}A_{2}}{A_{4}}}\\1&=&A_{1}+A_{2}\\1&=&A_{3}+A_{4}\\\end{array}}}
k 12 A 1 2 = − ( k 13 + k 12 ) A 1 A 3 − k 31 A 5 A 3 k 12 A 2 2 = − ( k 13 + k 12 ) A 2 A 4 + k 31 A 5 A 4 {\displaystyle {\begin{array}{ccc}k_{12}A_{1}^{2}&=&-\left(k_{13}+k_{12}\right)A_{1}A_{3}-k_{31}A_{5}A_{3}\\k_{12}A_{2}^{2}&=&-\left(k_{13}+k_{12}\right)A_{2}A_{4}+k_{31}A_{5}A_{4}\\\end{array}}}
k 12 A 1 2 = − ( k 13 + k 12 ) A 1 A 3 − k 31 A 2 A 3 A 2 = − ( k 13 + k 12 ) A 4 + k 31 A 4 k 12 A 1 = 1 − A 2 A 4 = ( 1 − A 3 ) {\displaystyle {\begin{array}{ccc}k_{12}A_{1}^{2}&=&-\left(k_{13}+k_{12}\right)A_{1}A_{3}-k_{31}A_{2}A_{3}\\A_{2}&=&{\frac {-\left(k_{13}+k_{12}\right)A_{4}+k_{31}A_{4}}{k_{12}}}\\A_{1}&=&1-A_{2}\\A_{4}&=&\left(1-A_{3}\right)\\\end{array}}}
k 12 A 1 2 = − ( k 13 + k 12 ) A 1 A 3 − k 31 A 2 A 3 A 2 = − ( k 13 + k 12 ) ( 1 − A 3 ) + k 31 ( 1 − A 3 ) k 12 A 1 = 1 + ( k 13 + k 12 ) ( 1 − A 3 ) − k 31 ( 1 − A 3 ) k 12 {\displaystyle {\begin{array}{ccc}k_{12}A_{1}^{2}&=&-\left(k_{13}+k_{12}\right)A_{1}A_{3}-k_{31}A_{2}A_{3}\\A_{2}&=&{\overset {\text{ }}{\frac {-\left(k_{13}+k_{12}\right)\left(1-A_{3}\right)+k_{31}\left(1-A_{3}\right)}{k_{12}}}}\\A_{1}&=&{\overset {\text{ }}{1+{\frac {\left(k_{13}+k_{12}\right)\left(1-A_{3}\right)-k_{31}\left(1-A_{3}\right)}{k_{12}}}}}\\\end{array}}}
c 10 := k 13 + 2 k 12 − k 31 k 12 c 11 := k 31 − k 13 − k 12 k 12 c 20 := − k 13 − k 12 + k 31 k 12 c 21 := k 13 + k 12 − k 31 k 12 A 1 = c 10 + c 11 A 3 A 2 = c 20 + c 21 A 3 {\displaystyle {\begin{array}{ccc}c_{10}&:=&{\frac {k_{13}+2k_{12}-k_{31}}{k_{12}}}\\c_{11}&:=&{\overset {\text{ }}{\frac {k_{31}-k_{13}-k_{12}}{k_{12}}}}\\c_{20}&:=&{\overset {\text{ }}{\frac {-k_{13}-k_{12}+k_{31}}{k_{12}}}}\\c_{21}&:=&{\overset {\text{ }}{\frac {k_{13}+k_{12}-k_{31}}{k_{12}}}}\\A_{1}&=&c_{10}+c_{11}A_{3}\\A_{2}&=&c_{20}+c_{21}A_{3}\end{array}}}
k 12 ( c 10 2 + 2 c 10 c 11 A 3 + c 11 2 A 3 2 ) = − ( c 10 k 13 + c 10 k 12 ) A 3 − ( c 11 k 13 + c 11 k 12 ) A 3 2 − k 31 c 20 A 3 − k 31 c 21 A 3 2 {\displaystyle k_{12}\left(c_{10}^{2}+2c_{10}c_{11}A_{3}+c_{11}^{2}A_{3}^{2}\right)=-\left(c_{10}k_{13}+c_{10}k_{12}\right)A_{3}-\left(c_{11}k_{13}+c_{11}k_{12}\right)A_{3}^{2}-k_{31}c_{20}A_{3}-k_{31}c_{21}A_{3}^{2}}
k 12 c 10 2 + ( 2 k 12 c 10 c 11 + c 10 k 13 + c 10 k 12 + k 31 c 20 ) A 3 + ( c 11 2 k 12 + c 11 k 13 + c 11 k 12 + k 31 c 21 ) A 3 2 = 0 {\displaystyle k_{12}c_{10}^{2}+\left(2k_{12}c_{10}c_{11}+c_{10}k_{13}+c_{10}k_{12}+k_{31}c_{20}\right)A_{3}+\left(c_{11}^{2}k_{12}+c_{11}k_{13}+c_{11}k_{12}+k_{31}c_{21}\right)A_{3}^{2}=0}
k 12 = 0.05 k 13 = 0.04 k 31 = 0.06 {\displaystyle {\begin{array}{ccc}k_{12}&=&0.05\\k_{13}&=&0.04\\k_{31}&=&0.06\end{array}}}