CPRT.I.A
Mit G ( T , p ) , F ( T , V ) {\displaystyle G(T,p),F(T,V)} : d G = d F + p d V + V d p {\displaystyle dG=dF+p\,dV+V\,dp} , + ∂ V ( T , p ) / ∂ T {\displaystyle +\partial V(T,p)/\partial T} , − ∂ p ( T , V ) / ∂ T {\displaystyle -\partial p(T,V)/\partial T} wie Übung 3.3.1a.
Mit G ( T , p ) , H ( S , p ) {\displaystyle G(T,p),H(S,p)} : d G = d H − T d S − S d T {\displaystyle dG=dH-T\,dS-S\,dT} , − ∂ S ( T , p ) / ∂ p {\displaystyle -\partial S(T,p)/\partial p} , + ∂ T ( S , p ) / ∂ p {\displaystyle +\partial T(S,p)/\partial p} wie Übung 3.3.1a.
Mit G ( T , p ) , U ( S , V ) {\displaystyle G(T,p),U(S,V)} : d G = d U − T d S − S d T + p d V + V d p {\displaystyle dG=dU-T\,dS-S\,dT+p\,dV+V\,dp} , − ∂ S ( T , p ) / ∂ p {\displaystyle -\partial S(T,p)/\partial p} , + ∂ T ( S , V ) / ∂ V {\displaystyle +\partial T(S,V)/\partial V} , + ∂ V ( T , p ) / ∂ T {\displaystyle +\partial V(T,p)/\partial T} , − ∂ p ( S , V ) / ∂ S {\displaystyle -\partial p(S,V)/\partial S} wie Übung 3.3.1a.