Eliminationsverfahrens:
| 2 x + 3 y = 11 7 x + 2 y = − 4 | | ⋅ 2 | ⋅ ( − 3 ) | 4 x + 6 y = 22 − 21 x − 6 y = 12 | | I | I I {\displaystyle \left|{\begin{matrix}2x+3y=11\\7x+2y=-4\end{matrix}}\right|{\begin{array}{l}\quad |\cdot 2\\\quad |\cdot (-3)\end{array}}\qquad \left|{\begin{matrix}4x+6y=22\\-21x-6y=12\end{matrix}}\right|{\begin{array}{l}\quad |\mathbf {I} \\\quad |\mathbf {II} \end{array}}}
4 x + 6 y − 21 x − 6 y = 22 + 12 − 17 x = 34 | : ( − 17 ) x = − 2 {\displaystyle {\begin{array}{rl}4x+6y-21x-6y&=22+12\\-17x&=34\qquad \quad |:(-17)\\x&=-2\end{array}}}