| x + y = 8 3 x + 5 y = 36 | → | x = 8 − y 3 x = 36 − 5 y | → | x = 8 − y x = 36 − 5 y 3 | | I | I I {\displaystyle \left|{\begin{array}{ll}x+y&=8\\3x+5y&=36\end{array}}\right|\rightarrow \left|{\begin{array}{ll}x&=8-y\\3x&=36-5y\end{array}}\right|\rightarrow \left|{\begin{array}{l}x=8-y\\x={\frac {36-5y}{3}}\end{array}}\right|\quad {\begin{array}{l}|\mathbf {I} \\|\mathbf {II} \end{array}}}
II=I
und daher
x = 8 − y = 8 − 6 = 2 {\displaystyle x=8-y=8-6=2}
Die Antwort ist:
x = 2 {\displaystyle x=2} und y = 6 {\displaystyle y=6}