Lösungen zu den Aufgaben zu Ing:_GdE:_Die_Spannungsquelle
U a = U 0 − I ∗ R i {\displaystyle U_{a}=U_{0}-I*R_{i}}
U a − U 0 = − I ∗ R i {\displaystyle U_{a}-U_{0}=-I*R_{i}}
U a − U 0 − I = R i {\displaystyle {\frac {U_{a}-U_{0}}{-I}}=R_{i}}
1 , 32 V − 1 , 5 V − 0 , 38 A = R i {\displaystyle {\frac {1,32V-1,5V}{-0,38A}}=R_{i}}
R_i = 0,47 Ω
R i = U a − U b I b − I a {\displaystyle R_{i}={\frac {U_{a}-U_{b}}{I_{b}-I_{a}}}}
Diese Formel gilt für Spannungsquellen, nicht für Verbraucher
R i = 11 , 9 V − 11 , 72 V 18 A − 10 A {\displaystyle R_{i}={\frac {11,9V-11,72V}{18A-10A}}}
R i = 0 , 18 V 8 A {\displaystyle R_{i}={\frac {0,18V}{8A}}}
R_i = 0{,}0225 Ω
U a = U 0 − I a ∗ R i {\displaystyle U_{a}=U_{0}-I_{a}*R_{i}}
U 0 = U a + I a ∗ R i {\displaystyle U_{0}=U_{a}+I_{a}*R_{i}}
U0 = 11,9 V + 10 A * 0,0225 Ω
U0 = 12,125 V
